If the echo is heard 0.5 seconds after the sound is emitted, and the speed of sound is 343 m/s, what is the distance to the reflecting surface?

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Multiple Choice

If the echo is heard 0.5 seconds after the sound is emitted, and the speed of sound is 343 m/s, what is the distance to the reflecting surface?

Explanation:
Sound travels to the surface and back in the given time, so the time corresponds to a round trip. The total distance the sound covers in 0.5 s is 343 m/s × 0.5 s = 171.5 meters. That distance includes the way out and the return, so the distance to the surface is half of that: 171.5 ÷ 2 = 85.75 meters.

Sound travels to the surface and back in the given time, so the time corresponds to a round trip. The total distance the sound covers in 0.5 s is 343 m/s × 0.5 s = 171.5 meters. That distance includes the way out and the return, so the distance to the surface is half of that: 171.5 ÷ 2 = 85.75 meters.

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